UI upgrades almost sure convergence
If $(X_n)$ is a martingale, $X_n\to X_\infty$ almost surely, and $(X_n)$ is uniformly integrable, then
$$ \mathbb E[|X_n-X_\infty|]\to 0. $$So the convergence is not only almost sure but also in $L^1$.
Consequence for expectations
Under the same assumptions,
$$ \mathbb E[X_\infty]
\lim_{n\to\infty}\mathbb E[X_n]
\mathbb E[X_0]. $$
UI version of optional stopping
If $(X_n)$ is a uniformly integrable martingale and $T$ is any stopping time, then
$$ \mathbb E[X_T]=\mathbb E[X_0]. $$This is the strongest version of OST and even allows $T=\infty$, with $X_T$ interpreted as $X_\infty$.